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Sagot :
The apparent weight of the pilot would be 619.48 N and the speed he would experience at weightlessness is 192. 97 m/s
What is apparent weight?
Apparent weight is a property of object that co-relates to the heaviness of the object.
It differs from the weight of an object as a result of the in-balance between the force acting on the object and an equal but opposite force
How to calculate the apparent weight
Formula:
Apparent weight = Real weight (mg) - m v∧2 ÷ r
Where m = mass
g = acceleration due to gravity = 9.8 m/s²
v = constant velocity = 2. 10 × 10∧2 m/s
r = radius = 3.80 × 10∧3 m
Note that weight = mg
m = weight ÷ g = 623 ÷ 9.8 = 63. 57 kg
a. Apparent wieight = 623 - (63. 57 × 2.10 × 10∧2 × 2.10 × 10∧2) ÷ 3.80 × 10∧3)
= 623 - (63.57 × 210) ÷ 3800
= 623 - 13377 ÷ 3800
= 623 - 3. 52
= 619.48 N
b. At weightless, weight = 0
Speed, V = √g× r = √ 9.8 × 3800 = √37,240 = 192. 97 m/s
Hence, The apparent weight of the pilot would be 619.48 N and the speed he would experience at weightlessness is 192. 97 m/s
Read more on apparent weight here:
https://brainly.com/question/11180653
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