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Identify the lateral area and surface area of a regular triangular pyramid with base edge length 6 cm and slant height 13 cm.

Sagot :

MrRoyal

The lateral area is 117 square centimeters and the surface area is 292.72 square centimeters

How to determine the lateral area?

The given parameters are:

  • Base length (b) = 6
  • Slant height (l) = 13

The lateral area is calculated using:

Lateral = 0.5 * (Perimeter of base) * Slant height

This gives

Lateral = 0.5 * (3 * 6) * 13

Evaluate

Lateral = 117

Hence, the lateral area is 117 square centimeters

How to determine the surface area?

The surface area is calculated using:

Surface = l²√3

This gives

Surface = 13² * √3

Evaluate

Surface = 292.72

Hence, the surface area is 292.72 square centimeters

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Answer:

L = 117 cm2 ; S = 132.6 cm2

Step-by-step explanation:

Substitute the known value of the base edge length s=6 cm into the formula for the perimeter of the regular triangle, P=3s.

P=3(6)=18

Therefore, the perimeter of the regular triangle is 18 cm.

Substitute the known values of the perimeter P=18 cm and the slant height l=13 cm into the formula for the lateral area of a regular pyramid, L=1/2Pl.

L=1/2(18)(13)=117

Therefore, the lateral area of the pyramid is 117 cm2.

The surface area of a regular pyramid with lateral area L and base area B is S=L+B, or S=1/2Pl+B.

The base of the regular triangular pyramid is the equilateral triangle. The area of the triangle with the base b and the height h is B=1/2bh.

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