Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A loaded freight car a with a mass of 24,000 kg moves at a constant velocity of 8 m/s on a horizontal railroad track and collides inelastically with an empty stationary car b with a mass of 8,000 kg. after the collision the cars stick to each other and moves like one object. what is the velocity of two cars after the collision?

Sagot :

The velocity of two cars after the collision will be 6 m/sec.The momentum of the body is given by the product of the mass and velocity of the body.

What is the law of conservation of momentum?

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

According to the law of conservation of momentum

Momentum before collision =Momentum after collision

[tex]\rm m_1v_1+m_2v_2=(m_1+m_2)V \\\\\ 24000 \ kg \times 8 m/sec+8000 \ kg \times 0 m/sec=(24000+8000)V\\\\ V= 6 m/sec[/tex]

Hence, the velocity of two cars after the collision will be 6 m/sec.

To learn more about the law of conservation of momentum refer;

https://brainly.com/question/1113396

#SPJ1

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.