At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

A loaded freight car a with a mass of 24,000 kg moves at a constant velocity of 8 m/s on a horizontal railroad track and collides inelastically with an empty stationary car b with a mass of 8,000 kg. after the collision the cars stick to each other and moves like one object. what is the velocity of two cars after the collision?

Sagot :

The velocity of two cars after the collision will be 6 m/sec.The momentum of the body is given by the product of the mass and velocity of the body.

What is the law of conservation of momentum?

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

According to the law of conservation of momentum

Momentum before collision =Momentum after collision

[tex]\rm m_1v_1+m_2v_2=(m_1+m_2)V \\\\\ 24000 \ kg \times 8 m/sec+8000 \ kg \times 0 m/sec=(24000+8000)V\\\\ V= 6 m/sec[/tex]

Hence, the velocity of two cars after the collision will be 6 m/sec.

To learn more about the law of conservation of momentum refer;

https://brainly.com/question/1113396

#SPJ1