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Sagot :
The probability of P(A|B) will be; P(A|B) = 2/5 = 0.4
How to deal with Venn Diagrams?
From the Venn diagram attached, it displays sports played by 10 students.
Let event A = The students play basketball.
Let event B = The student plays soccer.
Then the probability of P(A|B) will be;
P(A|B) = P(A ∩ B)/P(B)
P(A|B) = (2/10)/(5/10)
P(A|B) = 0.40
Read more about Venn Diagrams at; https://brainly.com/question/2099071
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