Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Ampère placed two 1.50-m wires parallel to each other so that they were 4.80 cm apart.
He delivered a current of 6.50 A to the wires. Both wires experienced an external
magnetic field of 2.71 X 10^−5 T. Determine the force on one of the wires.


Ampère Placed Two 150m Wires Parallel To Each Other So That They Were 480 Cm Apart He Delivered A Current Of 650 A To The Wires Both Wires Experienced An Extern class=

Sagot :

The force on one of the wires is determined as 1.76 x 10⁻⁴ N/m.

Force on the wire

The force between the two parallel wire is calculated as follows;

F = μI²L/2πr

where;

  • I is the current in the two wires
  • L is length of the wires
  • r is the distance between the wires

F = (4π x 10⁻⁷ x 6.5² x 1.5)/(2π x 0.048)

F = 2.64 x 10⁻⁴ N

Force per unit length of the wire

F/L =  2.64 x 10⁻⁴ N / 1.5

F/L = 1.76 x 10⁻⁴ N/m

Thus, the force on one of the wires is determined as 1.76 x 10⁻⁴ N/m.

Learn more about force here: https://brainly.com/question/12970081

#SPJ1

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.