Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
The force on one of the wires is determined as 1.76 x 10⁻⁴ N/m.
Force on the wire
The force between the two parallel wire is calculated as follows;
F = μI²L/2πr
where;
- I is the current in the two wires
- L is length of the wires
- r is the distance between the wires
F = (4π x 10⁻⁷ x 6.5² x 1.5)/(2π x 0.048)
F = 2.64 x 10⁻⁴ N
Force per unit length of the wire
F/L = 2.64 x 10⁻⁴ N / 1.5
F/L = 1.76 x 10⁻⁴ N/m
Thus, the force on one of the wires is determined as 1.76 x 10⁻⁴ N/m.
Learn more about force here: https://brainly.com/question/12970081
#SPJ1
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.