Answer:
Answer E is correct
Step-by-step explanation:
We know that,
[tex](x^ay^b)^c=x^a^cy^b^c[/tex]
Let us use the above to find the answer to this question.
Let us solve it now.
[tex](a^\frac{2}3} b^\frac{1}{3})^\frac{1}{2}[/tex]
[tex]a^\frac{2}3}^*^ \frac{1}{2} *b^\frac{1}{3}^*^\frac{1}{2}[/tex]
[tex]a^\frac{2*1}{3*2} * b^\frac{1*1}{3*2}[/tex]
[tex]a^\frac{2}{6} * b^\frac{1}{6}[/tex]
Here, we can simplify the [tex]a^\frac{2}{6}[/tex] as [tex]a^\frac{1}{3}[/tex] by dividing the numerator and denominator by 2.
Therefore, the answer will be,
[tex]a^\frac{1}{3} b^\frac{1}{6}[/tex]
