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Find the μ and o for the below data set. Is there an outlier?

15, 75, 88, 92, 100

Sagot :

The population mean (μ) is: 74

The standard deviation (σ) is: 30.6

There is an outlier, 15.

How to Find the Population Mean (μ) and the Standard Deviation (σ)?

Population mean (μ) = sum of data points / number of data points

Standard deviation (σ) = √(sum of squares/number of data points) = √(SS/n)

Given the data, 15, 75, 88, 92, 100:

Population mean (μ) = (15 + 75 + 88 + 92 + 100)/5 = 74

Standard deviation (σ) = √(4678/5)

σ = √935.6

σ = 30.6

15 is more smaller compared to most of the data points in the data, so, it is an outlier.

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