Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 3, negative 7) and (0, 2). Everything to the left of the line is shaded.
Which linear inequality is represented by the graph?

y < 3x + 2
y > 3x + 2
y < One-thirdx + 2
y > One-thirdx + 2


Sagot :

The inequality described can be written as:

y < 3x + 2.

How to get the inequality?

First, we know that we have a dashed line, and the region to the left of that line is shaded, then we will have:

y < line.

The linear equation is of the form:

y = a*x + b

Where a is the slope and b is the y-intercept.

Remember that if a line passes through the points (x₁, y₁) and (x₂, y₂), then the slope is:

[tex]a = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Here we know that the line passes through (-3, -7) and (0, 2), so the slope is:

[tex]a = \frac{2 - (-7)}{0 - (-3)} = 9/3 = 3[/tex]

And because the line passes through (0, 2), the y-intercept is 2, then the inequality is:

y < 3x + 2.

If you want to learn more about inequalities:

https://brainly.com/question/2516147

#SPJ1