Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A toy manufacturer wants to see how long, on average, a new toy captures children's attention. he tests children selected at random and finds that their mean attention span is minutes with a standard deviation of minutes. if we assume that attention spans are normally distributed, find a confidence interval for the mean attention span of children playing with this new toy. then find the lower limit and upper limit of the confidence interval.
carry your intermediate computations to at least three decimal places. round your answers to one decimal place. (if necessary, consult a list of formulas.)

lower limit:

upper limit:

Sagot :

Answer: Lower CI=21-t(0.025, 16)*7/sqrt(17)=21-2.12*7/sqrt(17)=17.4

upper CI=21+t(0.025, 16)*7/sqrt(17)=21+2.12*7/sqrt(17)=24.6

Explanation: Because there both close and equal

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.