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Consider the following cumulative probability distribution.
1 2 3
4
0.09 0.31 0.48 0.65 0.84
5
1
a. calculate a{xs 4). (round your answer to 2 decimal places.)
pox s 4)
p
b. calculate p{x= 3). (round your answer to 2 decimal places.)
p(x = 3)
#
+
e
10
19
34
m
c. calculate p(2 s x s 4). (round your answer to 2 decimal places.)
p(2 5 x 84)

Sagot :

okpalawalter8

The solution  [tex]P(x \leq 4),p{x= 3), p(2 \leq * \leq 4)[/tex]  is mathematically given as

  • [tex]P(2 \leq X \leq 4)=0.84[/tex]
  • P(X=3)= 0.17
  • [tex]P(2 < =X\leq 4)=0.53[/tex]

What is the solution [tex]P(x \leq 4),p{x= 3), p(2 \leq * \leq 4)[/tex]?

Generally, the equation for the Probability of P(X=3) is mathematically given as

b)

[tex]P(X=3) = P(X \leq 3)-P(X\leq 2)[/tex]

Therefore

[tex]P(X=3)= 0.65-0.48[/tex]

P(X=3)= 0.17

c)

[tex]P(2\leq X\leq 4) = P(X\leq 4)-P(X\leq 1)\\\\\\P(2\leq X\leq 4) = 0.84-0.31'[/tex]

[tex]P(2 < =X\leq 4)=0.53[/tex]

a)

[tex]P(2\leq X\leq 4)=0.84[/tex]

Read more about cumulative probability distribution.

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