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If 8. 0 ml of water is added to 2. 0 ml of a 0. 500 m koh solution, the concentration of koh is changed to.

Sagot :

Medunno13

Answer: 0.1 M

Explanation:

Originally, [tex]0.500=\frac{\text{moles of solute}}{0.002}[/tex], so there was 0.001 mol of KOH.

Now, there is 8.0+2.0=10.0 mL of solution, so the new concentration is:

[tex]\frac{0.001}{0.01}=\boxed{0.1 \text{ M}}[/tex]

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