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Sagot :
The angles for the first-order diffraction of the shortest and longest wavelengths of visible light are 22.33 ⁰ and 49.46 ⁰ respectively.
Angle for the first order diffraction
The angle for the first order diffraction is calculated as follows;
dsinθ = mλ
sinθ = mλ/d
For shortest wavelength (λ = 380 nm)
d = 1/10,000 lines/cm
d = 1 x 10⁻⁴ cm x 10⁻² m/cm = 1 x 10⁻⁶ m/lines
sinθ = (1 x 380 x 10⁻⁹)/(1 x 10⁻⁶)
sinθ = 0.38
θ = sin⁻¹(0.38)
θ = 22.33 ⁰
For longest wavelength (λ = 760 nm)
sinθ = (1 x 760 x 10⁻⁹)/(1 x 10⁻⁶)
sinθ = 0.76
θ = sin⁻¹(0.76)
θ = 49.46 ⁰
Learn more about diffraction here: https://brainly.com/question/16749356
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