At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
- The maximum shearing stress in hollow shaft is 66.125 MPa.
- The magnitude of angle of twist is 0.0279 rad.
- The power generated by the shaft is 157 kW.
What is power ?
Power in a rotating body like shaft is the product of Torque and the angular speed of that shaft.
P = Tω
The Torque is related to the shearing stress is
T = π/16 xτ(Do³ -Di³)
* Given is the Torque T= 7.5 kN.m, the inner diameter Di = 0.075m, outer diameter Do= 0.1m
Then, the maximum shearing stress will be
7.5 x 10³ = π/16 xτ x (0.1³ - 0.075³)
τ = 66.125 MPa
Thus, the shearing stress is 66.125 MPa.
* From the Torque equation
T/J = Gθ/l
Where, J = π/32 (Do⁴ -Di⁴) = 0.00000671 m⁴
l = length of shaft = 2m, modulus of rigidity G = 80GPa = 80x 10⁹ Pa.
Substitute the values, we get the angle of twist
7.5 x10³ /0.00000671 = 80x 10⁹xθ/2
θ = 0.0279 rad.
Thus, the angle of twist is0.0279 rad.
* Power generated by the shaft is
P = 2πNT/60
where N = revolution/ minute = 200
Put the values, we get
P = 2π x 200 x 7500/60
P = 157 kW.
Thus, the power generated is 157 kW.
Learn more about power.
https://brainly.com/question/15120631
#SPJ1
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
