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Kaminsky’s bronze sculpture is 5 feet in diameter, which is approximately 1.524 meters. If the sculpture was made of solid bronze, its weight could be approximated using the density of bronze , the volume, , in cubic meters, the mass, , in kilograms and applying the formula . Approximately, how many pounds would the sculpture weigh if it was made of solid bronze?

Sagot :

The weight of the spherical sculpture in pounds is approximately 251607 pounds

How to find the weight of the sculpture in pounds?

The sculpture is spherical and its made of solid bronze.

Therefore,

density  =  mass   /   volume

where

density  =  7700  kg  / m³

volume  = 4 / 3πr³

volume = 4/ 3  × 3.14  × 1.524³

volume  =  44.4574491494 / 3

volume = 14.8191497165 m³

Therefore,

mass = 7700 × 14.8191497165

mass = 114107.452817 kg

1 kg = 2.205 pounds

114107.452817 = ?

cross multiply

mass in pounds = 114107.452817 × 2.205

mass in pounds = 251606.933461

mass in pounds = 251607 pounds

learn more on pounds here: brainly.com/question/7930503

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