Answered

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Max w = 5y1 + 3y2
s. a.
y1 + y2 ≤ 50
2y1 + 3y2 ≤ 60
y1
, y2 ≥ 0

Sagot :

MrRoyal

The maximum value of the objective function is 330

How to maximize the objective function?

The given parameters are:

Max w = 5y₁ + 3y₂

Subject to

y₁ + y₂ ≤ 50

2y₁ + 3y₂ ≤ 60

y₁ , y₂ ≥ 0

Start by plotting the graph of the constraints (see attachment)

From the attached graph, we have:

(y₁ , y₂) = (90, -40)

Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂

w = 5 * 90 - 3 * 40

Evaluate

w = 330

Hence, the maximum value of the function is 330

Read more about objective functions at:

https://brainly.com/question/26036780

#SPJ1

View image MrRoyal
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