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the earnings of ahmed and bekhit are in the ratio 3:7 and that of bekhit and saeed is 4:9 and that of mohammed and saeed is 7:6. if the sum of the earnings of ahmed, bekhit, saeed, and mohammed is aed 52,950, then what are the earnings of mohammed?

aed 21,050
aed23,050
aed 24,050
aed33,050


Sagot :

Using a system of equations, it is found that the earnings of Mohammed are given by: 18,212 aed.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: Earnings of Ahmed.
  • Variable y: Earnings of Bekhit.
  • Variable z: Earnings of Saeed.
  • Variable w: Earnings of Mohammed.

The earnings of ahmed and bekhit are in the ratio 3:7, hence:

[tex]\frac{x}{y} = \frac{3}{7}[/tex]

[tex]3y = 7x[/tex]

[tex]y = \frac{7x}{3}[/tex]

That of bekhit and saeed is 4:9, hence:

[tex]\frac{y}{z} = \frac{4}{9}[/tex]

[tex]4z = 9y[/tex]

[tex]z = \frac{9y}{4}[/tex]

[tex]z = \frac{63x}{12}[/tex]

The ratio of mohammed and saeed is 7:6, hence:

[tex]\frac{z}{w} = \frac{7}{6}[/tex]

[tex]7w = 6z[/tex]

[tex]w = \frac{6z}{7}[/tex]

[tex]w = \frac{378x}{84}[/tex]

The sum is of 52950, hence:

[tex]x + y + z + w = 52950[/tex]

[tex]x + \frac{7x}{3} + \frac{63x}{12} + \frac{378x}{84} = 52950[/tex]

[tex]1099x = 52950 \times 84[/tex]

[tex]x = \frac{52950 \times 84}{1099}[/tex]

[tex]x = 4047[/tex]

Hence, Mohammed earnings in aed are given as follows:

[tex]w = \frac{378 \times 4047}{84} = 18212[/tex]

More can be learned about a system of equations at https://brainly.com/question/24342899

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