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Quadrilateral abcd has vertices a(1,0) b(5,0) c (7,2) d(3,2). use slope to prove that abcd is a parallelogram.

Sagot :

Medunno13

[tex]m_{\overline{AB}}=\frac{0-0}{1-5}=0\\m_{\overline{CD}}=\frac{2-2}{3-7}=0\\\\\therefore \overline{AB} \parallel \overline{CD} \text{ because } m_{\overline{AB}}=m_{\overline{CD}}[/tex]

[tex]m_{\overline{BC}}=\frac{2-0}{7-5}=1\\m_{\overline{AD}}=\frac{2-0}{3-1}=1\\\\\therefore \overline{BC} \parallel \overline{AD} \text{ because } m_{\overline{BC}}=m_{\overline{AD}}[/tex]

As ABCD has two pairs of opposite parallel sides, ABCD is a parallelogram.

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