Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Please help asap!! drag each tile to the correct box.
arrange the steps in the correct order to solve this trigonometric equation.
cos^2x = 3sin^2x

Sagot :

jw5394

cos²(x) = 3 sin²(x)

1 - sin²(x) = 3 sin²(x)

1 = 4 sin²(x)

1/4 = sin²(x)

± √(1/4) = sin(x)

± 1/2 = sin(x)

sin(x) = 1/2   or   sin(x) = -1/2

[x = arcsin(1/2) + 2nπ   or   x = π - arcsin(1/2) + 2nπ]

… … … or   [x = arcsin(-1/2) + 2nπ   or   x = π - arcsin(-1/2) + 2nπ]

(where n is any integer)

[x = π/6 + 2nπ   or   x = 5π/6 + 2nπ]

… … … or   [x = -π/6 + 2nπ   or   x = 7π/6 + 2nπ]

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.