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[tex]3x^2+8x+4=0[/tex]
Solve using the quadratic formula.

Sagot :

malayia49
Hopes this helps:

Answer: x = -2, -2/3

If it wrong I am sorry
loneguy

Answer:

[tex]x = -\dfrac 23\\\\x = -2[/tex]

Step by step explanation:

[tex]3x^2 +8x +4 =0\\\\\text{The quadratic formula,}~ x = \dfrac{-b\pm\sqrt{b^2 -4ac}}{2a}.\\\\\text{By comparing}~ 3x^2 +8x +4~ \text{with the standard form}~ ax^2 +bx +c,\\\\a = 3, ~b = 8 ,~ c = 4\\\\\text{Now,}~\\\\x = \dfrac{-8\pm\sqrt{8^2 -4 \times 3 \times 4}}{2(3)}\\\\\\~~~=\dfrac{-8\pm\sqrt{64-48}}{6}\\\\\\~~~=\dfrac{-8\pm\sqrt{16}}{6}\\\\\\~~~=\dfrac{-8\pm 4 }{6}\\[/tex]

[tex]x = \dfrac{-8+4}{6}=-\dfrac{4}{6}= -\dfrac 23\\\\x= \dfrac{-8-4}{6}= -\dfrac{12}{6}=-2[/tex]

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