Answer:
[tex]a= -\dfrac 23\\\\ b = -8\\\\ c = -47[/tex]
Step-by-step explanation:
[tex]b(x) = -\dfrac 23(x+6)^2 -23\\\\\\~~~~~~=-\dfrac 23(x^2 +2\cdot 6 \cdot x +6^2) -23\\\\\\~~~~~~=-\dfrac 23(x^2 +12x +36) -23\\\\\\~~~~~~=-\dfrac 23 x^2 - \dfrac{24}3 x - \dfrac{72}{3}-23\\\\\\~~~~~~=-\dfrac 23 x^2 -8x-24-23\\\\\\~~~~~~=-\dfrac 23x^2 -8x -47\\\\\text{By comparing}~ -\dfrac 23x^2 -8x -47~\text{with the standard form, }~ ax^2 +bx +c,\\\\a= -\dfrac 23,~ b = -8~ \text{and}~ c = -47[/tex]
