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Sagot :
Answer:11
Explanation: find the hypotenuse of the 1st triangle a^2 + b^2 = c^2 -> 9*9 + 5*5 = c^2
Which is 81+25 = c^2 -> 106 = c^2 now square root c = 10.3
Now you have the hypotenuse of the triangle on the left notice that the hypotenuse we just solved for is actually a leg for the triangle on the right. Now you can use the hypotenuse formula for x.
10.3^2 + 4^2 = x^2 -> 106.09 + 16 = x^2
Next, 122.09 = x^2 now we need to square root to isolate the square (2). x = 11.04 when rounded the closest radical is you answer x=11
Explanation: find the hypotenuse of the 1st triangle a^2 + b^2 = c^2 -> 9*9 + 5*5 = c^2
Which is 81+25 = c^2 -> 106 = c^2 now square root c = 10.3
Now you have the hypotenuse of the triangle on the left notice that the hypotenuse we just solved for is actually a leg for the triangle on the right. Now you can use the hypotenuse formula for x.
10.3^2 + 4^2 = x^2 -> 106.09 + 16 = x^2
Next, 122.09 = x^2 now we need to square root to isolate the square (2). x = 11.04 when rounded the closest radical is you answer x=11
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