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Sagot :
The equation of the line is 5y = 6x + 8 which passes through point C and perpendicular AB.
What is the slope?
The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).
[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have a triangle ABC is defined by the points A(2,9), B(8,4), and C(-3,-2).
The slope of the segment AB:
[tex]\rm m =\dfrac{4-9}{8-2}[/tex]
m = -5/6
The slope of the line perpendicular to AB:
Let M is the slope of the line:
mM = -1
(-5/6)M = -1
M = 6/5
The line:
y = Mx + c
y = (6/5)x + c
The line passing through the point C(-3, -2)
-2 = (6/5)(-3) + c
c = 8/5
y = (6/5)x + 8/5
5y = 6x + 8
Thus, the equation of the line is 5y = 6x + 8 which passes through point C and perpendicular AB.
Learn more about the slope here:
brainly.com/question/3605446
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