Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Answer:
Graphs can be used to represent functions
The value of a is less than 0.
The function is given as:
The parent function of f(x) is:
So, by comparison:
The function becomes:
Next, we identify the vertex (in this case, the vertex is the minimum point on the graph)
So, we have:
Substitute these values in
So, the function becomes
From the graph, we have the following point;
So, the function becomes
Subtract 2 from both sides
Square both sides
Divide both sides by -9
So, we have:
-1 is less than 0.
Hence, the value of a is less than 0.
Step-by-step explanation:
Answer:
The value of a in this function is 0
Step-by-step explanation:
The given function is
[tex]f(x) = a(x + k)^\frac{1}{n} + c.[/tex]
Here , f(x) is y = [tex]x^{\frac{1}{2} }[/tex] So , n = 2.
By substituting the value we get the function :
[tex]f(x) = a(x + k)^\frac{1}{2} + c.[/tex]
The vertex of the graphs are : (k, c) = (-5 ,2)
The function becomes:
[tex]f(x) = a(x + 5)^\frac{1}{2} + 2[/tex]
The following point on the graph shows : (x, y) = (-4 , 5)
The function becomes:
[tex]5 = a(-4+ 5)^\frac{1}{2} + 2\\5 = a(-9)^\frac{1}{2} + 2\\\\\3 = a(-9)^{\frac{1}{2} }(Subtract 2 from both side )\\\\9 = a (-9) ( Square both sides) \\\\-1 =a ( Divide both side by -9)\\[/tex]
a = -1
Here , -1 is less than zero
Hence , the value of a is less than o.
For more function related doubts visit:https://brainly.com/question/9834848
#SPJ1
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.