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Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the circle is 3 units. The center of the circle lies on the x-axis. The center of the circle lies on the y-axis. The standard form of the equation is (x – 1)² + y² = 3. The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

Sagot :

Completing the squares, the correct statements regarding the equation of the circle are given by:

  • The radius of the circle is 3 units
  • The center of the circle lies on the x-axis.
  • The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

What is the equation of a circle?

The equation of a circle of center [tex](x_0, y_0)[/tex] and radius r is given by:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

In this problem, the equation is given by:

x² + y² - 2x - 8 = 0.

Completing the squares:

(x - 1)² + y² = 8 + 1²

(x - 1)² + y² = 9.

Hence the center is (1,0), the radius is 3, and the correct statements are:

  • The radius of the circle is 3 units
  • The center of the circle lies on the x-axis.
  • The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

More can be learned about the equation of a circle at https://brainly.com/question/24307696

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