Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
The probability that the volume of a can chosen at random is ≥382 is 0.47725
Normal distribution probability
Probability is the likelihood or chance that an event will occur. For the given question, we need to calculate the z value as shown;
[tex]z=\dfrac{x-\mu}{\sigma}[/tex]
Given the following parameters
[tex]x=382mL\\\mu (mean)=372mL\\\sigma(S.D)=5mL[/tex]
Substitute
[tex]z=\dfrac{382-372}{5} \\z=\dfrac{10}{5}\\ z=2[/tex]
In order to calculate the probability that the volume of a can chosen at random is ≥382, we will look for (z≥2)
z≥2 according to probability table is equivalent to 0.47725
Learn more on normal distribution here: https://brainly.com/question/26822684
#SPJ1
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.