armassix2005
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*please help me out if you know how to solve, last person I asked just put a random awnser for point, the problem is bellow and there is a chart in the picture.*

6. In both Mr. Jacquez's Math 2 classes,
Period 2 and Period 3 were given the same test. The table below shows the results from the two classes.

a. Find the probability that a randomly selected student from Period 2's class failed the test.

b. Find the probability that a randomly selected student who failed the test is from Period 3's class​

Please Help Me Out If You Know How To Solve Last Person I Asked Just Put A Random Awnser For Point The Problem Is Bellow And There Is A Chart In The Picture6 In class=

Sagot :

Heather

     For both of these, we will divide the wanted outcome by the number of possible outcomes. We will end up with a decimal. A decimal multiplied by 100 becomes a percent.

[a] 50%

[tex]\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{student failed}}{\text{Period 2's class}} =\frac{12}{24} =0.5,\:0.5*100=50\%[/tex]

[b] 52%

[tex]\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{student failed from Period 3}}{\text{fails from both classes}} =\frac{13}{25} =0.52,[/tex]

    [tex]\displaystyle 0.52*100=52\%[/tex]

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