Answer:
59.0° (nearest tenth)
Step-by-step explanation:
This can be modeled as a right triangle (see attachment).
To find the angle of elevation (marked as [tex]x[/tex] on the attached diagram), use the tan trig ratio:
Tan trigonometric ratio
[tex]\sf\tan(\theta)=\dfrac{O}{A}[/tex]
where:
- [tex]\theta[/tex] is the angle
- O is the side opposite the angle
- A is the side adjacent the angle
Given:
- [tex]\theta = x[/tex]
- O = 10
- A = 6
Substitute the given values into the formula and solve for x:
[tex]\implies \sf\tan(\theta)=\dfrac{10}{6}[/tex]
[tex]\implies \sf\theta=\tan^{-1}\left(\dfrac{10}{6}\right)[/tex]
[tex]\implies \theta = \sf 59.03624...^{\circ}[/tex]
[tex]\implies \theta = \sf 59.0^{\circ}\:(nearest\:tenth)[/tex]
