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Sagot :
The probability that a student is a female or major in civil engineering is 62%
How to determine the probability?
Let A represent Female and B represents civil engineering.
So, we have:
P(A) = 49%
P(B) = 21%
P(A and B) = 8%
The required probability is calculated as:
P(A or B) = P(A) + P(B) - P(A and B)
This gives
P(A or B) = 49% + 21% - 8%
Evaluate
P(A or B) = 62%
Hence, the probability that a student is a female or major in civil engineering is 62%
Complete question
At a certain college, 49% of the students are female, and 21% of the students major in civil engineering. Furthermore, 8% of the students both are female and major in civil engineering. What is the probability that a randomly selected female student majors in civil engineering?
Read more about probability at:
https://brainly.com/question/251701
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