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how to solve for axis of symmetry for y=(x+2)(x-4)

Sagot :

Answer:

x = 1

Step-by-step explanation:

you can first find the two zeroes

that would be

x + 2 = 0

x - 4 = 0

x = {-2, 4}

then you average them

-2 + 4 = 2

2 / 2 = 1

the aos is 1

leaalibeg

Answer:

x=1

Step-by-step explanation:

[tex]y=x^{2} -4x+2x-8[/tex]
[tex]y=x^{2} -2x-8[/tex]   [tex](a=1, b=-2)[/tex]
[tex]x=-\frac{b}{2a} =\frac{-2}{2*1}[/tex]
[tex]x=1[/tex]
[tex]y=(x+2)(x-4), x=1[/tex]
[tex]y=(1+2)(1-4)[/tex]
[tex]y=-9[/tex]

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