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if Sin A = 3÷5 and Cos B =6÷10, where A and B are acute angles determine
Sin(A-B)​

Sagot :

culveryolanda46

Step-by-step explanation:

[tex] \sin( \alpha - \beta ) = \sin( \alpha ) \cos( \beta ) - \cos( \alpha ) \sin( \beta ) [/tex]

Using the Pythagorean theorem,

[tex] \cos( \alpha ) = \frac{4}{5} [/tex]

[tex] \sin( \beta ) = \frac{8}{10} [/tex]

[tex] \sin( \alpha - \beta ) = ( \frac{3}{5} )( \frac{3}{5} ) - ( \frac{4}{5} )( \frac{4}{5} )[/tex]

[tex] \frac{9}{25} - \frac{16}{25} = \frac{ - 7}{25} [/tex]

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