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Graph a line that contains the point (6, -5) and has a slope of -2/3.

Sagot :

We know that the equation of the line is in the form [tex]y=-\frac{2}{3}x+b[/tex]. To find b, we can use the fact that (6,-5) lies on the line, meaning that both sides of the equation are equal when x=6 and y=-5.

[tex]-5=-\frac{2}{3}(6)+b\\-5=-4+b\\b=-1[/tex]

Hence, the equation of the line is [tex]y=-\frac{2}{3}x-1[/tex], and its graph looks something like follows.

View image Medunno13
View image Medunno13

Step by Step Explanation:

View image ewitdatee29