ninjatelestic8907
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IM SO LOST PLS HELP ME

IM SO LOST PLS HELP ME class=

Sagot :

loneguy

[tex]~~~~~~~c = \dfrac{a^2 +3b}{4}\\\\\implies 4c = a^2 +3b\\\\\implies 3b = 4c-a^2\\\\\implies b = \dfrac{4c-a^2}{3}[/tex]

Hi1315

Answer:

b = [tex]\frac{(4c-a^2)}{3}[/tex]

Step-by-step explanation:

[tex]c=\frac{a^{2}+3b }{4}[/tex]

First, let us multiply both sides by 4.

4c = a² + 3b

Now let us take a² to the left side.

4c - a² = 3b

Now to make b as the subject let us divide both sides by 3.

[tex]\frac{(4c-a^2)}{3} =\frac{3b}{3}[/tex]

Therefore,

b = [tex]\frac{(4c-a^2)}{3}[/tex]      

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