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Sagot :
[tex]~~~~~~~c = \dfrac{a^2 +3b}{4}\\\\\implies 4c = a^2 +3b\\\\\implies 3b = 4c-a^2\\\\\implies b = \dfrac{4c-a^2}{3}[/tex]
Answer:
b = [tex]\frac{(4c-a^2)}{3}[/tex]
Step-by-step explanation:
[tex]c=\frac{a^{2}+3b }{4}[/tex]
First, let us multiply both sides by 4.
4c = a² + 3b
Now let us take a² to the left side.
4c - a² = 3b
Now to make b as the subject let us divide both sides by 3.
[tex]\frac{(4c-a^2)}{3} =\frac{3b}{3}[/tex]
Therefore,
b = [tex]\frac{(4c-a^2)}{3}[/tex]
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