Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

2 kq kg of ice at -4 degress Celsius is heated at Water at room temperature of 25 degrees Celsius .how much heat is absorbed ​

Sagot :

evgeniylevi

Answer:

893.8 [kJ].

Explanation:

1) the total heat can be calculated as

E=Q₁+Q₂+Q₃, where Q₁ - energy to heat the ice from -4 to 0; Q₂ - energy to melt the ice; Q₃ - to heat the water at 0 °C to 25 °C;

2) Q₁=λ*m*Δt₁, ⇒ Q₁=2100*2*4=16800 [J];

3) Q₂=c₂*m; ⇒ Q₂=333500*2=667000 [J];

3) Q₃=c₃*m*Δt₂; ⇒ Q₃=4200*2*25=210000 [j];

4) finally, the required heat is

E=16800+667000+210000=893800 [J]=893.8 [kJ].

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.