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The contents of two boxes are shown below. What is the probability of drawing a vowel from box 1 and an even number from box 2?
Box 1: A, B, C, D, E
Box 2: 1, 2, 3, 4, 5, 6, 7, 8, 9

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The Contents Of Two Boxes Are Shown Below What Is The Probability Of Drawing A Vowel From Box 1 And An Even Number From Box 2 Box 1 A B C D E Box 2 1 2 3 4 5 6 class=

Sagot :

Answer: 8/45

So, there are 2 vowels in box 1, A and E. Next, there are 4 even numbers in box 2, 2, 4, 6, and 8. Now, lets set up our equation. The equation will be amount/total amount. The equation will be 2/5 x 4/9, and the answer will be 8/45.

Answer:

vowel = 2/5

even number = 4/9

Step-by-step explanation:

vowel:

total of all letters in the box= 5

cound total number of vowels in the box = 2

[tex]\frac{2}{5}[/tex] because out of the 5 letters there is 2 vowels so overall you have a [tex]\frac{2}{5}[/tex]chance of pulling out a vowel.

Same logic for the even numbers one.

Even numbers:

total amount of numbers in the box: 9

total amout of even numbers: 4

[tex]\frac{4}{9}[/tex] because you have 9 numbers in total and you want the chnce of finding an even number. That means you need to put the amout of even numbers on top of the fraction and the total amount below.

OVERALL:

simple way of remembering it is:

p = total amout of the thing you want the probability of finding (in this case even numbers or vowels)

t = total amout of all options in the box (or any container)

[tex]\frac{p}{t}[/tex]