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3x+2y=39
5x-y=13
What is the solution to the system of equations

Sagot :

SomeoneInNeedOfHelp2

Answer:

I assume ur asking for x and y

Step-by-step explanation:

[tex]3x + 2y = 39 \: \: \: \: \: 1 \ \\ \ 5x - y = 13 \: \: \: \: \: \: \: \: 2 \\ y = 5x - 13 \: \: \: \: \: \: \: \: 3 \\ 3 > 1 \\ 3x+ 2(5x - 13) = 39 \\ 3x + 10x - 26 = 39 \\ 13x = 39 + 26 \: \: \: \: \: \: ( \div 13) \\ x = 5 \\ x = 5 > 3 \\ y = 5(5) - 13 \\ y = 12[/tex]

Answer:

(5, 12 )

Step-by-step explanation:

3x + 2y = 39 → (1)

5x - y = 13 → (2)

multiplying (2) by 2 and adding to (1) will eliminate y

10x - 2y = 26 → (3)

add (1) and (3) term by term to eliminate y

13x + 0 = 65

13x = 65 ( divide both sides by 13 )

x = 5

substitute x = 5 into either of the 2 equations and solve for y

substituting into (1)

3(5) + 2y = 39

15 + 2y = 39 ( subtract 15 from both sides )

2y = 24 ( divide both sides by 2 )

y = 12

solution is (5, 12 )

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