Answer:
Step-by-step explanation:
We will look for a line that has the general form of y = mx + b, where m is the slope and b the y-intercept (the value of y when x = 0).
A line parallel to y=2x-1 will have the same slope, 2.
We can write y = 2x + b for the new line. We need to find b. We can use the given point in this equation and solve for b:
y = 2x + b
2 = 2(4) + b for (4,2)
2 = 8 + b
x = -6
The parallel line to y=2x-1 that goes through point (4,2) is:
y = 2x-6
See the attached graph.
Hi student, let me help you out! :)
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We are asked to write the equation of the line that passes through (4, 2) and is parallel to y=2x-1.
[tex]\triangle~\fbox{\bf{KEY:}}[/tex]
Since the slope of the given line is 2, the slope of the line parallel to this one is also 2.
y=2x+c
Where: 2 is the y-coordinate of the point, and 4 is the x-coordinate.
Now, substitute 2 for y and 4 for x:
[tex]\longmapsto\sf{2=2(4)+c}[/tex]
Simplify!
[tex]\longmapsto\sf{2=8+c}[/tex]
Subtract 8 from both sides of the equal sign:
[tex]\longmapsto\sf{2-8=c}[/tex]
[tex]\longmapsto\sf{-6=c}[/tex]
Hope it helps you out! :D
Ask in comments if any queries arise.
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