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Sagot :
Answer:
secM = [tex]\frac{17}{15}[/tex]
Step-by-step explanation:
secM = [tex]\frac{1}{cosM}[/tex]
cosM = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{MN}{LM}[/tex] = [tex]\frac{15}{17}[/tex] , then
secM = [tex]\frac{1}{\frac{15}{17} }[/tex] = [tex]\frac{17}{15}[/tex]
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