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Given: ABCD is a parallelogram.

Prove: ∠A ≅ ∠C and ∠B ≅ ∠D

Parallelogram A B C D is shown.

By the definition of a ▱, AD∥BC and AB∥DC.

Using, AD as a transversal, ∠A and ∠
are same-side interior angles, so they are
. Using side
as a transversal, ∠B and ∠C are same-side interior angles, so they are supplementary. Using AB as a transversal, ∠A and ∠B are same-side interior angles, so they are supplementary.

Therefore, ∠A is congruent to ∠C because they are supplements of the same angle. Similarly, ∠B is congruent to ∠
.

Sagot :

A parallelogram is a quadrilateral with four sides and the opposite sides of the parallelogram are equal and parallel.

How to show the proof?

In the given figure, AB||DC. AD is the transversal, such that:

∠A + ∠D = 180-degrees.

The parallelogram is a quadrilateral with equal such that the interior angles present on the same side of the transversal are supplementary. The sum of supplementary angles is equal to 180-degrees.

From the theorem of same-side interior angles, the supplementary angles present on the parallel lines must be intersected by a transversal.

From the property of transversal, the interior angles on the same side of the transversal are supplementary. Therefore, ∠A and ∠D are supplementary and their sum is equivalent to 180-degrees.

Learn more about parallelogram on:

brainly.com/question/15584566

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