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Which are the solutions of x2 = –7x – 8?

StartFraction 7 Over 2 EndFraction minus StartFraction StartRoot 17 EndRoot Over 4 EndFraction comma StartFraction 7 Over 2 EndFraction + StartFraction StartRoot 17 EndRoot Over 4 EndFraction
StartFraction negative 7 Over 2 EndFraction minus StartFraction StartRoot 17 EndRoot Over 4 EndFraction comma StartFraction negative 7 Over 2 EndFraction + StartFraction StartRoot 17 EndRoot Over 4 EndFraction
StartFraction 7 minus StartRoot 17 EndRoot Over 2 EndFraction comma StartFraction 7 + StartRoot 17 EndRoot Over 2 EndFraction
StartFraction negative 7 minus StartRoot 17 EndRoot Over 2 EndFraction comma StartFraction negative 7 + StartRoot 17 EndRoot Over 2 EndFraction

Sagot :

facundo3141592

The solutions of the given quadratic equation are:

[tex]x = \frac{-7 + \sqrt{17} }{2} \\\\x = \frac{-7 - \sqrt{17} }{2}[/tex]

How to get the solutions of the quadratic equation?

Here we have the quadratic equation:

[tex]x^2 = -7x - 8[/tex]

To solve it, we can rewrite it as:

[tex]x^2 + 7x + 8 = 0[/tex]

Now if we use Bhaskara's formula, we get the solutions:

[tex]x = \frac{-7 \pm \sqrt{(7)^2 - 4*1*(8)} }{2} \\\\x = \frac{-7 \pm \sqrt{17} }{2}[/tex]

Then the two solutions are:

[tex]x = \frac{-7 + \sqrt{17} }{2} \\\\x = \frac{-7 - \sqrt{17} }{2}[/tex]

If you want to learn more about quadratic equations:

https://brainly.com/question/1214333

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