Answered

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Eliminate the parameter:
x = 2cost-1 y = 3sint+ 4

Sagot :

caylus

Answer:

Hi,

Step-by-step explanation:

[tex]\left\{\begin {array} {ccc}x&=&2*cos(t)-1\\y&=&3*sin(t)+4\\\end{array}\right.\\\\\\\left\{\begin {array} {ccc}\dfrac{x+1}{2}&=&cos(t\\\dfrac{y-4}{3}&=&sin(t)\\\end{array}\right.\\\\Squaring\\\\\boxed{(\dfrac{x+1}{2})^2+(\dfrac{y-4}{3})^2&=1}\\[/tex]

The curve is an ellipse having (-1,4) as center and half-axis (2 and 6)

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