Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Ask your questions and receive precise answers from experienced professionals across different disciplines. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

solve for x
[tex] \bold{x^{2} + 6x + 5 = 0}[/tex]

ty! ~

Sagot :

IndependentArtist

Answer:

x²+6x+5=0

On comparing with the equation

ax² + bx + c = 0

a=1, b = 6 and c = 5

Now

b²– 4ac = 6² – 4 x 1 x 5 = 36 - 20 = 16

[tex]x = \frac{ - b \:± \: \sqrt{b {}^{2} - 4ac } }{2a} \\ \\ x = \frac{ - 6\:± \: \sqrt{16 } }{2 \times 1} \\ \\ x = \frac{ - 6± {4} }{2} \\ \\ x = \frac{ - 6 + {4} }{2} \: \: or \: \: x = \frac{ - 6 - {4} }{2} \\ \\ \implies \: x = \frac{ \cancel-2 }{ \cancel2}^{-1 }\: \: or \: \: x = \frac{ \cancel-10 }{ \cancel2}^{-5}\\ \\ \implies \: { \blue{\fbox{ \: x = - 1 \: \: \: or \: \: \:x = - 5}}}[/tex]

juwairiyah53

[tex] {x}^{2} + 6x + 5 = 0 \\ \\ {x}^{2} + 5x + x + 5 = 0 \\ \\ x(x + 5) + 1(x + 5) = 0 \\ \\ (x + 1)(x + 5) = 0.[/tex]

[tex]x = - 1 \\ x = - 5.[/tex]

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.