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Sagot :
The equation of the circle with center at (2,-4) and tangent to the line x = -2 is given by:
(2) (x - 2)² + (y + 4)² = 16
What is the equation of a circle?
The equation of a circle of center [tex](x_0, y_0)[/tex] and radius r is given by:
[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]
The circle has center at (2,-4), hence [tex]x_0 = 2, y_0 = -4[/tex].
The center is tangent to the line x = -2, hence it has a point at x = -2, since |-2 - 2| = 4, r = 4 -> r² = 16.
Hence the equation of the circle is given by:
(2) (x - 2)² + (y + 4)² = 16
More can be learned about the equation of a circle at https://brainly.com/question/24307696
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