Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
The inequality to represent the temperatures at which the gas in the truck will remain in liquid form is -40 < x < 140
Part A: The inequality
Let the temperature of the gas be represented with x.
When the temperature hits −40° F (or below), the gas freezes.
This means that the gas temperature must always exceed −40° F to remain being a liquid
i.e x > −40
Also, when the temperature hits 140° F (or above), the gas evaporates.
This means that the gas temperature must always be less than 140° F to remain being a liquid
i.e x < 140
So, we have:
x > −40 and x < 140
Rewrite as:
-40 < x and x < 140
Combine both inequalities
-40 < x < 140
Hence, the inequality to represent the temperatures at which the gas in the truck will remain in liquid form is -40 < x < 140
Part B: The description of the graph
In (a), we have:
-40 < x < 140
The end points of the inequalities use a less than sign.
Less than signs are represented by open circle.
Hence, the graph would use an open circle, and intervals between -40 and 140 would be shaded
Part C: Would −49° F gas remained in liquid form?
We have:
-40 < x < 140
The number -49 is not in the range -40 < x < 140
Hence, the gas would not remain in liquid form (in fact, it would freeze because it is less than -40)
Read more about inequalities at:
https://brainly.com/question/24372553
#SPJ1
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.