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Sagot :
The coordinates of the vertex for the quadratic function are given as follows: (100,10).
What is the vertex of a quadratic equation?
A quadratic equation is modeled by:
[tex]y = ax^2 + bx + c[/tex]
The vertex is given by:
[tex](x_v, y_v)[/tex]
In which:
- [tex]x_v = -\frac{b}{2a}[/tex]
- [tex]y_v = -\frac{b^2 - 4ac}{4a}[/tex]
In this problem, the function is given as follows:
y = -x²/1000 + x/5
y = -0.001x² + 0.2x.
Hence the coefficients are a = -0.001, b = 0.2, c = 0 and the coordinates of the vertex are given as follows:
- [tex]x_v = -\frac{0.2}{2(-0.001)} = 100[/tex]
- [tex]y_v = -\frac{(0.2)^2}{4(-0.001)} = 10[/tex]
More can be learned about the vertex of a quadratic function at https://brainly.com/question/24737967
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