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can you help me figure of the value of y?and possible x (I think I got it)​

Can You Help Me Figure Of The Value Of Yand Possible X I Think I Got It class=

Sagot :

The values of x and y from the figure are 22.5 and 10 respectively

Vertical angles

The angles that meet at a point X are equal and vertically opposite

From the diagram shown

6x - 5 = 8x - 50

6x - 8x = -50 +  5

-2x = -45

x = 22.5

Similarly

2y + 30 = 3y + 20

2y - 3y = 20 - 30

-y = -10

y = 10

Hence the values of x and y from the figure are 22.5 and 10 respectively

Learn more on vertical angles here: https://brainly.com/question/1673457

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[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's solve ~

Since the two lines intersects each other we can conclude that :

  • 6x - 5 = 8x - 50

and

  • 2y + 30 = 3y + 20

[ That's because they form vertical opposite angle pair ]

So, let's solve for x and y ~

[tex]\qquad \sf  \dashrightarrow \:6x - 5 = 8x - 50[/tex]

[tex]\qquad \sf  \dashrightarrow \:8x - 6x = - 5 + 50[/tex]

[tex]\qquad \sf  \dashrightarrow \:2x = 45[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = \dfrac{45}{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 22.5[/tex]

And

[tex]\qquad \sf  \dashrightarrow \:2y + 30 = 3y + 20[/tex]

[tex]\qquad \sf  \dashrightarrow \:3y - 2y = 30 - 20[/tex]

[tex]\qquad \sf  \dashrightarrow \:y = 10[/tex]

I hope the steps are clear ~ let me know if you have doubts ~