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Find the value of x.
Round to the nearest tenth.
B
63
142°
61
A
C
X
x = [?
X
Law of Cosines: c² = a² + b² - 2ab cos C


Sagot :

The value of x in the triangle using the cosine rule is 22.1 degrees.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Cosine rule is used to show the relationship between the sides and angles of a triangle. It is given by:

c² = a² + b² - 2ab cos C

Where a, b, c are the sides and C is the angle opposite side c.

Using cosine rule:

8² = 14² + 19² - 2(14)(19) * cos(x)

cos(x) = 0.9267

x = 22.1°

The value of x in the triangle using the cosine rule is 22.1 degrees.

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Using the law of Cosines, the value of x to the nearest tenth is 77.8

Law of Cosines

From the question, we are to determine the value of x

Using the law of Cosines

c² = a² + b² - 2ab cos C

c is the unknown side length  

a and b are the given side lengths

and C is the included angle

From the given information,

a = 63

b = 62

C = 142°

Then,

x² = 63² + 61² -2×63×61 cos 142°

x² = 3969 + 3721 -7686(-0.788)

x�� = 7690 + 6056.568

x² = 13746.569

x = √13746.569

x = 77.8

Hence, the value of x to the nearest tenth is 77.8

Learn more on Law of Cosines here: https://brainly.com/question/23282500

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