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The polynomial function p(x)=x3−4x2+ax+20 has (x+1) as one of its factors.

What would be the remainder when p(x) is divided by (x+2)


Sagot :

The remainder when p(x) is divided by (x+2) is; -79.

What is the remainder when p(X) is divided by (X+1)?

Since one of it's factors is (x+1), it follows that P(-1) = 0.

Hence; 0 = (-1)³ -4(-1)² -a +20

a = 15.

Hence, the polynomial is; p(x)=x3−4x2+15x+20

The remainder when p(x) is divided by (x+2) is;

p(-2) = (-2)³ -4(-2)² + 15(-5) +20

p(-2) = -8 -16 -75 +20

p(-2) = -79.

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