The solution to the triangle is A = 92.0, B = 47.9 and C = 40.1
How to solve the triangle?
The figure is not given;
However, the question can still be solved without it
The given parameters are:
a = 31, b = 23, and c = 20
Calculate angle A using the following law of cosine
a² = b² + c² - 2bc * cos(A)
So, we have:
31² = 23² + 20² - 2 * 23 * 20 * cos(A)
Evaluate
961 = 929 - 920 * cos(A)
Subtract 929 from both sides
32 =- 920 * cos(A)
Divide both sides by -920
cos(A) = -0.0348
Take the arc cos of both sides
A = 92.0
Calculate angle B using the following law of sine
a/sin(A) = b/sin(B)
So, we have:
31/sin(92) = 23/sin(B)
This gives
31.0189 = 23/sin(B)
Rewrite as:
sin(B) =23/31.0189
Evaluate
sin(B) =0.7415
Take arc sin of both sides
B = 47.9
Calculate angle C using:
C = 180 - 92.0 - 47.9
Evaluate
C = 40.1
Hence, the solution to the triangle is A = 92.0, B = 47.9 and C = 40.1
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