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A bungee jumper jumps off a bridge and bounces up and down several times.
She finally comes to rest 16 m below the bridge from which she just jumped.
If her mass is 50 kg and the spring constant of the bungee cord is 35 N/m,
how much energy was lost due to air resistance while she was bouncing?
(Recall that g = 9.8 m/s²)
OA. 5420 N
OB. 3360 N
OC. 4280 N
O D. 6550 N

Sagot :

onyebuchinnaji

The energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.

Conservation of energy

The amount of energy lost due to  air resistance while she was bouncing is determined from the principle of conservation of energy.

ΔE = P.E - Ux

ΔE = mgh - ¹/₂kx²

ΔE = (50)(9.8)(16) - ¹/₂(35)(16)²

ΔE = 3,360 J

Thus, the energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.

Learn more about energy here: https://brainly.com/question/13881533

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