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Sagot :
The linear regression equation that represents this data set is equal to y = 11.7x + 48.2 and an estimate of the calendar year is 2022.
How to write the linear regression equation?
First of all, we would determine the slope of the given data set by using this formula:
[tex]Slope = \frac{\sum (x-\bar x)(y-\bar y)}{\sum (x-\bar x)^2}[/tex]
For the sample mean (years), we have:
∑x = 0 + 1 + 2 + 3
∑x = 6.
∑x² = 0² + 1² + 2² + 3²
∑x² = 14.
For the sample mean (profits), we have:
∑y = 46 + 57 + 84 + 76
∑y = 263.
∑xy = (0 × 46) + (1 × 57) + (2 × 84) + (3 × 76)
∑xy = 453.
Now, we can determine the slope:
[tex]Slope = \frac{4(453) - 6(263)}{4(14) - 6^2} \\\\Slope = \frac{234}{20}[/tex]
Slope, m = 11.7.
For the intercept, we have:
[tex]Intercept = \frac{14(263) - 6(453)}{4(14) - 6^2} \\\\Intercept = \frac{964}{20}[/tex]
Intercept, c = 48.2.
Therefore, the linear regression equation is given by:
y = 11.7x + 48.2.
Since the profit would reach 144,000 dollars, the calendar year would be calculated as follows:
144 = 11.7x + 48.2
11.7x = 144 - 48.2
11.7x = 95.8
x = 95.8/11.7
x = 8.2.
For the calendar year, we have:
Year = 2014 + 8.2
Year = 2022.2 ≈ 2022.
Read more on linear regression here: https://brainly.com/question/16793283
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